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login.php: Properly link to logout page when already logged in

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Signed-off-by: canyonknight <canyonknight@gmail.com>
Signed-off-by: Lukas Fleischer <archlinux@cryptocrack.de>
This commit is contained in:
canyonknight 2012-11-21 09:58:55 -05:00 • committed by Lukas Fleischer
parent 0e923bd11e
commit e383205eda
1 changed files with 1 additions and 1 deletions
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2
web/html/login.php
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@ -17,7 +17,7 @@ html_header('AUR ' . __("Login"));
<?php if (isset($_COOKIE["AURSID"])): ?> <?php if (isset($_COOKIE["AURSID"])): ?>
<p> <p>
<?= __("Logged-in as: %s", '<strong>' . username_from_sid($_COOKIE["AURSID"]) . '</strong>'); ?> <?= __("Logged-in as: %s", '<strong>' . username_from_sid($_COOKIE["AURSID"]) . '</strong>'); ?>
<a href="<?php get_uri('/logout/'); ?>">[<?= __("Logout"); ?>]</a> <a href="<?= get_uri('/logout/'); ?>">[<?= __("Logout"); ?>]</a>
</p> </p>
<?php elseif (!$DISABLE_HTTP_LOGIN || (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'])): ?> <?php elseif (!$DISABLE_HTTP_LOGIN || (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'])): ?>
<form method="post" action="<?= get_uri('/login') ?>"> <form method="post" action="<?= get_uri('/login') ?>">